I want to find a list of evenly spaced numbers over a given interval. What Python function should I use?

+1 vote

You can use the **linspace()** function of Numpy. It returns the evenly spaced numbers over a given interval. You can provide the start, end, and count of numbers you want as arguments.

Here is an example:

>>> import numpy as np

>>> a=np.linspace(0, 1, 20)

>>> a

array([0. , 0.05263158, 0.10526316, 0.15789474, 0.21052632,

0.26315789, 0.31578947, 0.36842105, 0.42105263, 0.47368421,

0.52631579, 0.57894737, 0.63157895, 0.68421053, 0.73684211,

0.78947368, 0.84210526, 0.89473684, 0.94736842, 1. ])

>>>

You can also use **arrange()** function of Numpy. You need to provide the start, end, and step size as arguments.

>>> np.arange(1, 20, 5)

array([ 1, 6, 11, 16])

>>>